WAEC GCE 2016 Mathematics theory/objective Ouestions and Answers expo
VERIFIED WAEC GCE 2016 MATHS QUESTIONS
AND ANSWERS
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Saturday, 10th September, 2016
General Mathematics (Essay&objective)
9.30am-3.30pm
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MATHS OBJ:
1-10: ABCDDCBCDB
11-20: DCCCCACDBA
21-30: BDBAABDACA
31-40: CCACBDCDBD
41-50: DBCBDABBBC
1a )
6whole 1 / 2 – 3 whole 2/ 5 / 2whole 1 / 2 – 1
whole 3/ 5 25 / 4- 17 / 5 , / 5/ 2- 8/ 5 125 – 68 / , 20 , / 25 – 16, / 10
==> 57 / 20 / 9/ 10
=57 / 20 /9 / 10
=57 / 20 x 10 / 9
=57 / 20 x 10 / 9
=57 / 18
= 3whole 1 / 6
(2a)
m/m-y+2 = r/y+r-1
r(m-y+2)=m(y+r-1)
rm-ry+2r = my+mr-m
rm+2r-m+mr=my+ry
y(m+r)=rm+2r-m+mr
y=2mr+2r-m/m+r
(2b)
p[one of them owns a bicycle]
[60/100+70/100] – [40/100 + 30/100]
Because % of boys that don’t have bicycle =
40/100
% of girls without bicycle = 30/100
=130/100 – 70/100
=60/100
=0.6
3a)
c= -1, y= -3, z= -4 and w= -7
x^2 – y^2 / 2w – z
(-1)^3 – (-3)^2 / 2(-7) -(-4)
= -1-9/+4+4
3b)
< MQN + < NQO = 90 degree
< MNQ + 46 = 90 degree
< MNQ = 90 – 46 degree
< MNQ = 44 degree
Considering < MNQ
y + n + MQN = 180 degree
y + 44 + 44 = 180
y = 180 – 88
Y =92 degree
4a)
2/3(1-4x) -1/2(5-3x)
less/equal to 1/4(7+9x)-1/3 multiply through by 12
8(1-4x) -6(5-3x) less/equal to
3(7+9x)-4 8-32x-30+18x less/equal to 21+27x-4
-32x+18x – 27x less/equal to
21-4+30-8 -41x less/equal to
39 x less/equal to
-39/41
4b)
DRAW THE ANGLE
from DTMR/ Tan65degree = TR/3
TR = 3Tan65 = 3 x 22.1445
From DRMB
Tan20 = RB/3
RB = 3Tan20 = 3 x 0.3640
= 1.092m H = TR+RB
= 6.4335 + 1.092 = 7.5255
= 7.53m
= -10/-10
= 1
(5)
Area of shed segment = Area of Sector – Area of Triangle
=tita/360 *pie r^2 – (1/2 abSinc )
=90/ 360 * 22/7*7^2) – 1/2 * 7 *7*sin90degree
=154/4 – 42/2
=(754-98)/4
=56/4
=14cm^2
Cost of painting it = 14*750
=N10500
==============================
(6a )
Taxable income = x
25 /100 x x /1
= 14, 000
25 x= 1400000
X =1400000 / 25
X = 560000
Total income =
56 ,000 / 4 x 5
=N70,000
(6b)
Education = 2 /5
Clothes = 1 /6
Food = 3/ 8
Expenditure = 2 /5 + 1/ 6 + 3 /8
48 + 20 + 45 / 120
= 113 /120 * 36, 000 / 1
Le 39 , 000
Savings annually = Le 21 ,000
To save Le 63,000.00
To save Le 63,000 / 2100 yrs
= 30 years
(7a)
diagram
(7b)
Angula difference in long(tita)=42-12
tita=30 degree
(7bi)
lenght of chord Xy=2Rsin tita/2
XY=2*6400*Sin 30/2
=2*6400*sin15 degree
=12800*0.2588
=3.312.64km
=3312.64km
=3310km(to the nearest 10km)
(7bii)
let the angle that the chord xy substends at the centre of the earth be alpha degree
diagram
sin alpha/2= opp/hyp=/NY/ /6400
/NY/= 1/2 /XY/= 1/2 * 3312.64
=1656.32km
sin alpha/2= 1656.32/6400
sin alpha/2= 0.25888
alpha/2= sin^-1(0.2588)
alpha/2=14.999
alpha=14.999 *2
alpha= 29.998
alpha= 30.0 degree (to 1 dp)
(7biii)
XY bar= tita/360 * 2pie R cos lat
=30 degeree/360 * 2*3.142 * 6400* cos60
XY bar= 30/360 * 2* 3.142* 6400* 0.5
XY bar=1675.73 km
(8a)
Drawing
(8bi)
Using Pythagoras theory
| xz|^ =550^2 320^2
= 302500 102400 =404900
xz=√ 404999
=636 km( 3 s.f )
Total distance = 320 550 636
= 1506km
(8bii )
Using SOHCAHTOA
Tan z = 320 /550
Z = Tan ^-1(320 /550)
Z = Tan ^-1(0.5818)
Z = 30 degree
From the diagram in 8 a
Bearing of X from Z = 55 30
= 085 degree or N85 degree E
(9a)
3log 10^2 – 2log10^3= 1+ log 10(1/x)
log 10^6 – log10^6= log 10 + log 10(1/x)
log 10^6 / 10^6= log 10* 10(1/x)
1=10^1+1/x
1+10(x+1 /x)
x+1 /x =0
x+1=0
x=1
(9b)
h=8m
speed =3km/hr
time= 3mins=3/60 =1/20hr
(i)
Distance= 2 pie r= speed * time
2* 22/7 *r= 3* 1/20
44r/7 = 3/20
44r= 7*3 /20
r=7*3/ 44*20
r=0.02386km
r=23.86km
r=24m(nearest whole n)
(ii)
vol= pie r^2 h
=22/7 * 24^2* 8
=14,482.29m^3
vol= 14,482m^2(nearest whole number
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